What is the output PEP of 500 volts peak-to-peak across a 50-ohm load?
Answer625 watts
A 500-volt peak-to-peak sine wave has 250 volts peak and about 176.8 volts RMS. Squaring that and dividing by 50 ohms gives 625 watts.
General · FCC ELEMENT 3
G5B14
General · FCC Element 3 · answer reveals automatically